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First solution in Clear category for Reverse Roman Numerals by rossras
def reverse_roman(roman_string):
table = {
'M': 1000,
'D': 500,
'C': 100,
'L': 50,
'X': 10,
'V': 5,
'I': 1
}
nums = [table[ch] for ch in roman_string]
result = last = 0
while nums:
num = nums.pop()
if num < last:
result -= num
else:
result += num
last = num
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert reverse_roman('VI') == 6, '6'
assert reverse_roman('LXXVI') == 76, '76'
assert reverse_roman('CDXCIX') == 499, '499'
assert reverse_roman('MMMDCCCLXXXVIII') == 3888, '3888'
print('Great! It is time to Check your code!');
Aug. 10, 2018