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First solution in Clear category for Digit Stack by wo.tomasz
def digit_stack(commands):
stack = []
output = 0
for c in commands:
if c.split(" ")[0] == 'PUSH':
stack.append(int(c.split(" ")[1]))
elif c == 'POP' and len(stack) > 0:
output += stack.pop(-1)
elif c == 'PEEK' and len(stack) > 0:
output += stack[-1]
return output
if __name__ == '__main__':
print("Example:")
print(digit_stack(["PUSH 3", "POP", "POP", "PUSH 4", "PEEK",
"PUSH 9", "PUSH 0", "PEEK", "POP", "PUSH 1", "PEEK"]))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert digit_stack(["PUSH 3", "POP", "POP", "PUSH 4", "PEEK",
"PUSH 9", "PUSH 0", "PEEK", "POP", "PUSH 1", "PEEK"]) == 8, "Example"
assert digit_stack(["POP", "POP"]) == 0, "pop, pop, zero"
assert digit_stack(["PUSH 9", "PUSH 9", "POP"]) == 9, "Push the button"
assert digit_stack([]) == 0, "Nothing"
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Jan. 24, 2023