Combining the first names of beloved celebrity couples to a catchy shorthand for mass media consumption turns out to be simple to automate.

Start by counting how many maximal groups of consecutive vowels (aeiou, as to keep this problem simple, the letter y is always a consonant) exist inside the first name. For example, "brad" and "jean" have one vowel group, "jeanie" and "britain" have two, and "angelina" and "alexander" have four. Note that a vowel group can contain more than one vowel, as in the word "queueing" with an entire fiver.

If the first name has only one vowel group, keep only the consonants before that group and lose everything else. For example, "ben" becomes "b", and "brad" becomes "br". Otherwise, if the first word has n > 1 vowel groups, keep everything before the second last vowel group n – 1. For example, "angelina" becomes "angel" and "alexander" becomes "alex".

Concatenate that string with the string that you get by removing all consonants from the beginning of the second name.

Input: Two strings (str).

Output: String (str).

Examples:

assert brangelina("brad", "angelina") == "brangelina"
assert brangelina("angelina", "brad") == "angelad"
assert brangelina("sheldon", "amy") == "shamy"

Preconditions:

• first and second names are guaranteed to consist of the 26 lowercase English letters, and each name will have at least one vowel and one consonant somewhere.

The mission was taken from Python CCPS 109. It is taught for Ryerson Chang School of Continuing Education by Ilkka Kokkarinen