In this mission, you need to convert a nested cipher dictionary to a plain text to according to the following steps. This conversion is opposite to one in Cipher Dict mission.

1. Starting from top dictionary, take keys and sort them in correct order into a block of digits. Blocks order should be strictly alternated and the first block must be ascending. Check value (dict as well) of each key in its turn to find next block and get new keys to check later in their turns.

2. Concatenate all founded blocks into single decimal number.

3. Convert this decimal value into a hexadecimal number and convert the result to string.

The description may be confusing, so let's look at the example.

Input: A cipher data as a dictionary.

Output: An original text as a string.

get_plain({1: {6: {3: {}}},2: {6: {5: {}}, 9: {0: {}, 5: {}}},3: {4: {5: {}}},6: {6: {4: {}}}}) == 'python'
get_plain({1: {1: {8: {8: {8: {0: {0: {1: {3: {9: {6: {},9: {}}}, 6: {2: {0: {}}}}}, 1: {8: {0: {1: {1: {}, 7: {}, 9: {}}, 7: {0: {}, 2: {}, 3: {}}}, 5: {7: {8: {}}}}},2: {1: {0: {2: {2: {}}}}, 4: {8: {9: {0: {}, 5: {}}}}}}}}}}}}) == 'You can read me.'

How it’s used: (It may not be valuable as a cipher, but it will be useful for studying character code conversion and dictionary structure.)

Precondition: The text contain only ASCII symbols >= 32.