Fuck yea!!! Solved in one line!
def checkio(text):return max([(text.lower().count(i)-0.001*ord(i),i) for i in "abcdefghijklmnopqrstuvwxyz" if text.lower().count(i)])[1]
However it is not python way to write such brainfucking code. But it was funny)))
task.most-wanted-letterCreated: March 16, 2015, 10:30 p.m.
Updated: June 20, 2016, 12:51 p.m.
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