def checkio(text):return max([(text.lower().count(i)-0.001*ord(i),i) for i in "abcdefghijklmnopqrstuvwxyz" if text.lower().count(i)])[1]
However it is not python way to write such brainfucking code. But it was funny)))
The Most Wanted Letter
SEARCHING TIPS
==============
author:[username] - Returns posts by user
associated with the given user.
tag:[tag_name1],[tag_name2], ... - Returns
posts associated with the given tag(s).
phrase - Returns posts that contain the word
or set of words in title or text.
