Hi,
I believe the description of the 16-bit packed messages is incorrect.
The statement says:
Bit 7 6 5 4 3 2 1 0
Octet-nth
1 b7 b6 b5 b4 b3 b2 b1 b0
2 b15 b14 b13 b12 b11 b10 b9 b8
So, going from left to right, the octet i contains the 8 less significant bits (lsb) and octet i+1 the 8 most significant bits (msb).
However, to match the expected output, I had to do the opposite: consider that octet i has the 8 msb and octet i+1 the lsb.
Created at: 2014/03/12 18:57; Updated at: 2014/03/13 01:01