Aggregate and Count
You have a list of values where each element is a list of two values. First is a name and the second one is counter.
What you need to do is to aggregate those values into a dict, which is easy, you can simply use function dict for that. But, name is not unique, so if you find more that one elements with the same name, you should sum their counters in the aggregated dict.
Input: List of list of two elelemnts - str and int.
Output: Int.
Example:
assert aggregate_and_count([["a", 1], ["b", 2]]) == {"a": 1, "b": 2}
assert aggregate_and_count([["a", 1], ["a", 2]]) == {"a": 3}
assert aggregate_and_count([["a", 1], ["b", 2], ["c", 3], ["a", 5]]) == {
"a": 6,
"b": 2,
"c": 3,
}
assert aggregate_and_count([["a", 1]]) == {"a": 1}
CheckiO Extensions allow you to use local files to solve missions. More info in a blog post.
In order to install CheckiO client you'll need installed Python (version at least 3.8)
Install CheckiO Client first:
pip3 install checkio_client
Configure your tool
checkio --domain=py config --key=
Sync solutions into your local folder
checkio sync
(in beta testing) Launch local server so your browser can use it and sync solution between local file end extension on the fly. (doesn't work for safari)
checkio serv -d
Alternatevly, you can install Chrome extension or FF addon
checkio install-plugin
checkio install-plugin --ff
checkio install-plugin --chromium
Read more here about other functionality that the checkio client provides. Feel free to submit an issue in case of any difficulties.
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