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First solution in Clear category for Xs and Os Referee by yukirin
def checkio(result):
table = []
for i in range(3): table += [result[i], [x[i] for x in result]]
table += [[result[i][i] for i in range(3)], [result[i][2 - i] for i in range(3)]]
return'X' if any(l.count('X') == 3 for l in table) else 'O' if any(l.count('O') == 3 for l in table) else 'D'
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([
"X.O",
"XX.",
"XOO"]) == "X", "Xs wins"
assert checkio([
"OO.",
"XOX",
"XOX"]) == "O", "Os wins"
assert checkio([
"OOX",
"XXO",
"OXX"]) == "D", "Draw"
assert checkio([
"O.X",
"XX.",
"XOO"]) == "X", "Xs wins again"
March 29, 2015
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