First speedy solution for Xs and Os Referee by rus5719n - python coding challenges

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First solution in Speedy category for Xs and Os Referee by rus5719n

def checkio(game_result):
    res = "D"
    for i in range(3):
        if game_result[0][i] == game_result[1][i] == game_result[2][i] != ".": res = game_result[0][i]
        if game_result[i][0] == game_result[i][1] == game_result[i][2] !=".": res = game_result[i][0]
    if game_result[0][0] == game_result[1][1] == game_result[2][2] != ".": res = game_result[0][0]
    if game_result[2][0] == game_result[1][1] == game_result[0][2] != ".": res = game_result[2][0]
    return res

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert checkio([
        "X.O",
        "XX.",
        "XOO"]) == "X", "Xs wins"
    assert checkio([
        "OO.",
        "XOX",
        "XOX"]) == "O", "Os wins"
    assert checkio([
        "OOX",
        "XXO",
        "OXX"]) == "D", "Draw"
    assert checkio([
        "O.X",
        "XX.",
        "XOO"]) == "X", "Xs wins again"

Dec. 26, 2015

Comments:

mmartsinenko on Dec. 9, 2024, 11:39 a.m.
<p>This solution stores the result in a variable res and updates it whenever a winning condition is detected. While this avoids returning immediately, the overall logic is verbose and lacks the compactness of my solution. The repeated checks across rows, columns, and diagonals add some redundancy, making it slightly slower.</p>

List, list and list again

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