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First solution in Clear category for Xs and Os Referee by martin_b
# migrated from python 2.7
import re
def checkio(game_result):
# join the array to one long string
# row - search for 3 equal game characters next to each other: r"([OX])\1{2}"
# column - search for 3 equal game characters separated by any 3 characters: r"([OX]).{3}\1.{3}\1"
# diagonals - like a column, different offsets: r"([OX]).{4}\1.{4}\1" and r"([OX]).{2}\1.{2}\1"
res=re.search(r"([OX])(\1{2}|.{3}\1.{3}\1|.{4}\1.{4}\1|.{2}\1.{2}\1)","-".join(game_result))
if res!=None: return res.group(0)[0]
return "D"
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([
"X.O",
"XX.",
"XOO"]) == "X", "Xs wins"
assert checkio([
"OO.",
"XOX",
"XOX"]) == "O", "Os wins"
assert checkio([
"OOX",
"XXO",
"OXX"]) == "D", "Draw"
assert checkio([
"O.X",
"XX.",
"XOO"]) == "X", "Xs wins again"
Dec. 1, 2015
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