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Lambda + reduce + max solution in Clear category for Worth of Words by infestum
from functools import reduce
from typing import List
VALUES = {'e': 1, 'a': 1, 'i': 1, 'o': 1, 'n': 1, 'r': 1,
't': 1, 'l': 1, 's': 1, 'u': 1, 'd': 2, 'g': 2,
'b': 3, 'c': 3, 'm': 3, 'p': 3, 'f': 4, 'h': 4,
'v': 4, 'w': 4, 'y': 4, 'k': 5, 'j': 8, 'x': 8,
'q': 10, 'z': 10}
def worth_of_words(words: List[str]) -> str:
reducer = lambda item: reduce(lambda accum, item: accum + VALUES[item], item, 0)
return max([(reducer(word), word) for word in words])[1]
Nov. 5, 2021