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Worth of Words solution in Clear category for Worth of Words by JimmyCarlos
def getScore(s):
score = 0
for c in s:
if any(c == a for a in "eaionrtlsu"): score += 1
elif any(c == a for a in "dg"): score += 2
elif any(c == a for a in "bcmp"): score += 3
elif any(c == a for a in "fhvwy"): score += 4
elif any(c == a for a in "k"): score += 5
elif any(c == a for a in "jx"): score += 8
elif any(c == a for a in "qz"): score += 10
return score
def worth_of_words(words):
return max(words,key=lambda x:getScore(x))
Aug. 3, 2018
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