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lambda + itertools.groupby() solution in Clear category for Words Order by maksimus
from itertools import groupby
words_order = lambda text, words: [e for e, _ in groupby([el for el in text.split(" ") if el in words])] == words
if __name__ == '__main__':
print("Example:")
print(words_order('hi world im here', ['world', 'here']))
# These "asserts" are used for self-checking and not for an auto-testing
assert words_order('hi world im here', ['world', 'here']) == True
assert words_order('hi world im here', ['here', 'world']) == False
assert words_order('hi world im here', ['world']) == True
assert words_order('hi world im here',
['world', 'here', 'hi']) == False
assert words_order('hi world im here',
['world', 'im', 'here']) == True
assert words_order('hi world im here',
['world', 'hi', 'here']) == False
assert words_order('hi world im here', ['world', 'world']) == False
assert words_order('hi world im here',
['country', 'world']) == False
assert words_order('hi world im here', ['wo', 'rld']) == False
assert words_order('', ['world', 'here']) == False
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Dec. 14, 2020