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easy loop solution in Clear category for Weekend Counter by furtadobb
from datetime import date, timedelta
def checkio(from_date, to_date):
"""
Count the days of rest
"""
count = 0
for i in range((from_date - to_date).days * - 1 + 1):
from_date += timedelta(days=1 if i != 0 else 0)
if from_date.weekday() == 5 or from_date.weekday() == 6:
count += 1
return count
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(date(2013, 9, 18), date(2013, 9, 23)) == 2, "1st example"
assert checkio(date(2013, 1, 1), date(2013, 2, 1)) == 8, "2nd example"
assert checkio(date(2013, 2, 2), date(2013, 2, 3)) == 2, "3rd example"
Oct. 4, 2020