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First solution in Clear category for Verify Anagrams by dominikbrandon
def verify_anagrams(first_word, second_word):
charUsed = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
array = first_word.split()
for i in range(0, len(array)):
array[i] = array[i].lower()
for j in range(0, len(array[i])):
charUsed[ord(array[i][j]) - ord('a')] += 1
array = second_word.split()
for i in range(0, len(array)):
array[i] = array[i].lower()
for j in range(0, len(array[i])):
charUsed[ord(array[i][j]) - ord('a')] -= 1
for i in range(0,len(charUsed)):
if charUsed[i] != 0:
return False
return True
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(verify_anagrams("a", 'z'), bool), "Boolean!"
assert verify_anagrams("Programming", "Gram Ring Mop") == True, "Gram of code"
assert verify_anagrams("Hello", "Ole Oh") == False, "Hello! Ole Oh!"
assert verify_anagrams("Kyoto", "Tokyo") == True, "The global warming crisis of 3002"
Oct. 25, 2016