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First solution in Clear category for The Angles of a Triangle by bswitaj
def checkio(a, b, c):
if a+b<=c or a+c<=b or c+b<=a:
return [0,0,0]
else:
import cmath
import math
x=cmath.acos((a**2+b**2-c**2)/(2*a*b))
y=cmath.acos((a**2+c**2-b**2)/(2*a*c))
z=cmath.acos((c**2+b**2-a**2)/(2*c*b))
#f=0.00
x=x.real
y=y.real
z=z.real
#x=x.remove("-")
# y=y.remove("-")
#z=z.remove("-")
w=1.5707963267948966*4
x=round(x*360/w)
y=round(y*360/w)
z=round(z*360/w)
f=[]
f.append(x)
f.append(y)
f.append(z)
#replace this for solution
#x=round(x,0)
print (x)
print (y)
print (z)
return sorted(f)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(3, 4, 5) == [37, 53, 90], "Egyptian triangle"
assert checkio(4, 4, 4) == [60, 60, 60], "All sides are equal"
assert checkio(3, 4, 5) == [37, 53, 90], "Egyptian triangle"
assert checkio(2, 2, 5) == [0, 0, 0], "It's can not be a triangle"
Oct. 16, 2017