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One liner (but not clear) solution in Creative category for Tree Walker by CDG.Axel
def tree_walker(tree, target):
# not readable, but one-liner ) readable is below
return 1 if tree == target else 0 if type(tree) not in (dict, list) else \
sum(tree_walker(node, target) for node in (tree if type(tree) is list else tree.values()))
"""
if tree == target:
return 1
if type(tree) == dict:
return sum(tree_walker(node, target) for node in tree.values())
if type(tree) == list:
return sum(tree_walker(node, target) for node in tree)
return 0
"""
if __name__ == '__main__':
print("Example:")
print(tree_walker([1, "2", 3, [[3], 1, {1: "one"}]], 1))
# These "asserts" are used for self-checking and not for an auto-testing
assert tree_walker([1, "2", 3, [[3], 1, {1: "one"}]], 1) == 2, "1st"
assert tree_walker({"one": 1, "two": [{1: "one", 2: "two"}, 1, "1", "one"]}, 1) == 2, "2nd"
assert tree_walker({"one": [1, 2], "two": [{1: "one", 2: "two"}, [1, 2], "1", "one"]}, [1, 2]) == 2, "3rd"
assert tree_walker(5, 5) == 1, "4th"
assert tree_walker([5, 6, 2, "1"], 1) == 0, "5th"
assert tree_walker([[dict()], [[[3], [3, 5]]], [], []], 3) == 2, "6th"
assert tree_walker([{1: "one"}, {2: "two"}, "two", ["two", {"two": "one"}]], "two") == 3, "7th"
print("Coding complete? Click 'Check' to earn cool rewards!")
Oct. 20, 2021
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