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First solution in Clear category for Three Words by tomasz.pucka
def checkio(words):
words_counter=0
number_presence=False
for char in words:
ascii=ord(char)
if((ascii<48 or ascii>57) and char!=" "):
number_presence=False
elif(char==" " and number_presence==False):
words_counter+=1
elif(char==" " and number_presence==True):
words_counter=0
elif(ascii>=48 and ascii<=57):
words_counter=0
number_presence=True
if(words_counter>=3):
return True
if((ascii<48 or ascii>57) and words_counter==2):
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Oct. 26, 2016