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Flag words as 1/0, check for '111' solution in Clear category for Three Words by tetrahydrofuran
def checkio(words: str) -> bool:
# Convert words to 1/0 flag, concatenate as string, check for 111
# e.g. "He is 123 man" -> 1101 -> False
words = [1 if not i.isnumeric() else 0 for i in words.split(' ')]
words = ''.join([str(i) for i in words])
return '111' in words
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print('Example:')
print(checkio("Hello World hello"))
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Oct. 4, 2020
