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Word counter with selections solution in Clear category for Three Words by pseidel
def checkio(words):
words = words.split()
if len(words) < 3:
return False
count = 0
for word in words:
if word.isalpha():
count += 1
else:
count = 0
if count == 3:
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print('Example:')
print(checkio("Hello World hello"))
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
July 26, 2019
