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First solution in Clear category for Three Words by pikaneska
def checkio(words):
words=words+' '
n=0
i=0
for i in range(len(words)-1):
if ('a'<=words[i]<='z') or ('A'<=words[i]<='Z'):
if words[i+1]==' ':
n=n+1
elif words[i+1] in ['0','1','2','3','4','5','6','7','8','9']:
n=0
if n>=3:
return True
break
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 16, 2016
