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Counter approach solution in Clear category for Three Words by lesnikow
def checkio(words: str) -> bool:
"""Checks whether there are three consecutive alpabetical words in the given group of words."""
count = 0
for word in words.split():
if word.isalpha():
count += 1
else:
count = 0
if count >= 3: return True
return False
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Dec. 13, 2020