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First solution in Clear category for Three Words by aieozn
def checkio(words):
suma=0;
words=words+' ';
for i in range(len(words)):
if ord(words[i])==32:
suma=suma+1;
if suma==3:
return True;
if ord(words[i])>=48 and ord(words[i])<=57:
suma=-1;
return False;
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 26, 2016