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First solution in Uncategorized category for Three Words by PiotrKrol
def checkio(words):
words = words.split()
i = 0
j = 0
wynik = False
for i in range(len(words)):
if words[i].isalpha():
j+=1
if j == 3:
wynik = True
else:
j = 0
return wynik
Oct. 16, 2017