First creative solution for Three Words by LLluma - python coding challenges

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First solution in Creative category for Three Words by LLluma

from itertools import islice

def checkio(words):
    return any(all(map(str.isalpha, trigram)) for trigram in zip( *(islice(words.split(' '), i, None) for i in range(3)) ))

#These "asserts" using only for self-checking and not necessary for auto-testing

April 22, 2014

Comments:

danikmil on Nov. 27, 2014, 3:20 p.m.
brilliant! :)

hezhe88 on Nov. 16, 2015, 5:27 p.m.
similar but without islice: <pre class='brush: python'>def checkio(words): return any(all(map(unicode.isalpha, trigram)) for trigram in zip(*(words.split()[i:] for i in range(3)))) </pre> <a href="http://www.checkio.org/mission/three-words/publications/hezhe88/python-27/second/">http://www.checkio.org/mission/three-words/publications/hezhe88/python-27/second/</a>

kraytor on April 20, 2017, 7:17 a.m.
hard to understand oneliner. Some refactor: def checkio(words): <pre class='brush: python'>trigrams = (words.spilt()[i:] for i in range(3)) check = lambda trig: all(el.isalpha() for el in trig) three_words = (check(trigram) for trigram in zip(*trigrams)) return any(three_words) </pre>

Strings and Integers

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