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First solution in Uncategorized category for Three Words by HappyBerry
def checkio(words):
t=words.split()
print(t)
x=0
z=False
lb=['0','1','2','3','4','5','6','7','8','9']
for w in t:
q=0
for l in lb:
if(w.find(l)!=-1):
q=q+1
if(q>0):
x=0
else:
x=x+1
if(x==3):
z=True
print(z)
return z
Oct. 20, 2017