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"Three Words" solution in Clear category for Three Words by FUbaer
def checkio(words: str) -> bool:
count = 0 # create a count variable
for i in words.split(): # go through the splited string
if not i.isalpha(): # if element i contain not letters
count = 0 # set counter to zero
else: # all characters are letters
count += 1 # count up
if count == 3: # if the counter is 3
return True # we have three words in a raw
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print('Example:')
print(checkio("Hello Wolrld helllo"))
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Feb. 3, 2020
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