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Three words solution in Clear category for Three Words by Druggist
def checkio(words):
words = words.split(' ')
if len(words) < 3:
return False
for i in range(1,len(words) - 1):
if not words[i-1].isdigit() and not words[i].isdigit() and not words[i+1].isdigit():
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 25, 2016
