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Flag solution in Clear category for Three Words by Dm_Ch
def checkio(words: str) -> bool:
A = words.split(sep=' ')
flag = False
for n in range(len(A)-2):
if (A[n]+A[n+1]+A[n+2]).isalpha():
flag = True
return flag
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print('Example:')
print(checkio("Hello World hello"))
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
March 20, 2021