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Three words solution in Clear category for Three Words by CyrylWilczek
def checkio(words):
perhaps = False
words = words.split()
if (len(words) > 2):
i = 0
while (i + 2 < len(words)):
if words[i].isalpha():
if words[i+1].isalpha():
if words[i+2].isalpha():
perhaps = True
i += 1
return perhaps
Nov. 5, 2017
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