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First solution in Clear category for Three Words by Bartosz_M
def checkio(words):
numbers = []
for i in range(101):
numbers.append(str(i))
words = words + " "
counter = 0
for letter in words:
if letter in numbers:
counter = 0
if letter == " " and last_letter not in numbers:
counter += 1
print(letter)
print(counter)
if counter == 3:
return True
last_letter = letter
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 8, 2016