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The Stone Wall solution in Clear category for The Stone Wall by JimmyCarlos
def stone_wall(wall):
wall = [row for row in wall.split("\n") if row != ""]
column_depth=lambda s:s.count("#")
H,W = len(wall),len(wall[0])
return min(range(W), key=lambda C:column_depth("".join(wall[R][C] for R in range(H))))
Sept. 7, 2018