One-line lambda solution in Clear category for The Most Frequent by Bronepoezd
most_frequent = lambda data: max(data, key=lambda x: data.count(x))
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
'a', 'b', 'c',
]) == 'a'
assert most_frequent(['a', 'a', 'bi', 'bi', 'bi']) == 'bi'
Oct. 19, 2017