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4-liner: calc solution in Clear category for The Brick Factory Problem by przemyslaw.daniel
def crosses(k: int, s: int = None) -> int:
if s is None:
return (k // 2) * ((k - 1) // 2) * ((k - 2) // 2) * ((k - 3) // 2) // 4
return (k // 2) * ((k - 1) // 2) * (s // 2) * ((s - 1) // 2)
Jan. 6, 2024
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