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math.prod solution in Clear category for The Brick Factory Problem by Phil15
from math import prod
def crosses(k: int, s: int = None) -> int:
if s is None:
return prod((k - i) // 2 for i in range(4)) // 4
return prod((n - i) // 2 for n in (s, k) for i in range(2))
Jan. 2, 2024
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