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First solution in Clear category for Texas Referee by Sim0000
from itertools import combinations
from collections import Counter
RANKS = "23456789TJQKA"
SUITS = "scdh"
STRAIGHT_FLUSH = 8 # why python doesn't have enum?
FOUR_OF_KIND = 7
FULL_HOUSE = 6
FLUSH = 5
STRAIGHT = 4
THREE_OF_KIND = 3
TWO_PAIR = 2
ONE_PAIR = 1
HIGH_CARD = 0
def texas_referee(cards_str):
def calc_hand(cards : tuple) -> tuple:
""" returns hand, additional_information.
where additional_information is sorted cards by a rule depends on cards """
flush = all(c[1] == cards[0][1] for c in cards)
sorted_cards = sorted(cards, reverse=True)
straight = all(sorted_cards[i][0] == sorted_cards[i + 1][0] + 1 for i in range(4))
ranks_count = Counter(c[0] for c in cards).most_common(2)
rank1, count1 = ranks_count[0]
rank2, count2 = ranks_count[1]
sorted_by_rank1 = lambda x:(x[0]+20, x[1]) if x[0] == rank1 else x
sorted_by_rank12 = lambda x:(x[0]+40, x[1]) if x[0] == rank1 else (x[0]+20, x[1]) if x[0] == rank2 else x
if straight and flush:
hand, sort_rule = STRAIGHT_FLUSH, None
elif count1 == 4:
hand, sort_rule = FOUR_OF_KIND, sorted_by_rank1
elif (count1, count2) == (3, 2):
hand, sort_rule = FULL_HOUSE, sorted_by_rank1
elif flush:
hand, sort_rule = FLUSH, None
elif straight:
hand, sort_rule = STRAIGHT, None
elif count1 == 3:
hand, sort_rule = THREE_OF_KIND, sorted_by_rank1
elif count1 == count2 == 2:
rank1, rank2 = max(rank1, rank2), min(rank1, rank2)
hand, sort_rule = TWO_PAIR, sorted_by_rank12
elif count1 == 2:
hand, sort_rule = ONE_PAIR, sorted_by_rank1
else:
hand, sort_rule = HIGH_CARD, None
return hand, sorted(cards, key=sort_rule, reverse=True)
# start here
cards = [(RANKS.find(s[0]), SUITS.find(s[1])) for s in cards_str.split(',')]
max_cards = max((c for c in combinations(cards, 5)), key=calc_hand)
return ','.join(RANKS[c[0]] + SUITS[c[1]] for c in sorted(max_cards, reverse=True))
April 9, 2015
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