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Striped Words solution in Clear category for Striped Words by narimiran
VOWELS = set("AEIOUY")
CONSONANTS = set("BCDFGHJKLMNPQRSTVWXZ")
def checkio(text):
txt = ''.join(c.upper() if c.isalnum() else ' ' for c in text).split()
total = 0
for word in txt:
if len(word) < 2:
continue
odd = set(word[1::2])
even = set(word[::2])
total += ((odd <= VOWELS and even <= CONSONANTS) or
(odd <= CONSONANTS and even <= VOWELS))
return total
# These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("My name is ...") == 3, "All words are striped"
assert checkio("Hello world") == 0, "No one"
assert checkio("A quantity of striped words.") == 1, "Only of"
assert checkio("Dog,cat,mouse,bird.Human.") == 3, "Dog, cat and human"
April 7, 2016
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