Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Striped Words by marcosrodrigues
def checkio(line: str) -> str:
Vowels = 'AEIOUY'
Consonants = 'BCDFGHJKLMNPQRSTVWXZ'
cont = 0
newline = ''
for c in line:
if c.upper() in Vowels:
newline += 'a'
elif c.upper() in Consonants:
newline += 'b'
elif not c.isalnum():
newline += ' '
else:
newline += c
for word in newline.split():
if 'aa' not in word and 'bb' not in word and word.isalpha() and len(word)>1:
cont += 1
return cont
if __name__ == '__main__':
print("Example:")
print(checkio('My name is ...'))
# These "asserts" are used for self-checking and not for an auto-testing
assert checkio('My name is ...') == 3
assert checkio('Hello world') == 0
assert checkio('A quantity of striped words.') == 1
assert checkio('Dog,cat,mouse,bird.Human.') == 3
print("Coding complete? Click 'Check' to earn cool rewards!")
Oct. 9, 2020
