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Long and boring solution in Clear category for Striped Words by Vulwsztyn
VOWELS = "AEIOUY"
CONSONANTS = "BCDFGHJKLMNPQRSTVWXZ"
def checkio(text):
text=text.replace('.',' ')
text=text.replace(',',' ')
text=text.upper()
o=0
for word in text.split():
s=0
i=0
if word[i] not in VOWELS and word[i] not in CONSONANTS:
s=1
if word[i] in VOWELS:
while i1:
o+=1
return o
Oct. 25, 2016