# Staircase

The easier problem Beat the previous asked you to greedily extract a strictly ascending sequence of integers from the given series of digits. For example, for digits equal to "31415926", the list of integers returned should be [3, 14, 15, 92], with the last original digit left unused.

Going somewhat against intuition, the ability to tactically skip some of the digits at will may allow the resulting list of integers to contain more elements than the list constructed in the previous greedy fashion. With this additional freedom, the example digit string "31415926" would allow the result [3, 4, 5, 9, 26] with one more element than the greedily constructed solution.

Your function should return the length of the longest list of ascending integers that can be extracted from digits. Note that you are allowed to skip one or more digits not just between two integers being extracted, but during the construction of each such integer.

Input: String (str).

Output: Integer (int).

Examples:

```assert staircase("100123") == 4
assert staircase("503715") == 4
assert staircase("0425494220946") == 6
assert staircase("04414952075836") == 7
```

The mission was taken from Python CCPS 109. It is taught for Ryerson Chang School of Continuing Education by Ilkka Kokkarinen

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CheckiO Extensions

CheckiO Extensions allow you to use local files to solve missions. More info in a blog post.

In order to install CheckiO client you'll need installed Python (version at least 3.8)

Install CheckiO Client first:

`pip3 install checkio_client`

`checkio --domain=py config --key=`

Sync solutions into your local folder

`checkio sync`

(in beta testing) Launch local server so your browser can use it and sync solution between local file end extension on the fly. (doesn't work for safari)

`checkio serv -d`

Alternatevly, you can install Chrome extension or FF addon

`checkio install-plugin`
`checkio install-plugin --ff`
`checkio install-plugin --chromium`

Read more here about other functionality that the checkio client provides. Feel free to submit an issue in case of any difficulties.

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