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First solution in Clear category for Speech Module by wrak
FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
HUNDRED = "hundred"
def checkio(number):
n=number
a=0
u = " ";
if n%100==0:
req= (FIRST_TEN[(n//100)-1],HUNDRED)
return u.join( req )
elif n>99:
a=n//100
n=n-100*(n//100)
b=n
n=n-10*(n//10)
c=n
print(n)
if b<10:
req= (FIRST_TEN[a-1],HUNDRED,FIRST_TEN[c-1])
return u.join( req )
elif b<13 and b>9:
req= (FIRST_TEN[a-1],HUNDRED,SECOND_TEN[n-(b//10)*10])
return u.join( req )
elif b<20:
req= (FIRST_TEN[a-1],HUNDRED)
return u.join( req )
else:
if c==0:
req= (FIRST_TEN[a-1],HUNDRED,OTHER_TENS[(b//10)-2])
return u.join( req )
else:
req= (FIRST_TEN[a-1],HUNDRED,OTHER_TENS[b//10-2],FIRST_TEN[c-1])
print (u.join( req ))
print(FIRST_TEN[a-1],HUNDRED,OTHER_TENS[b//10-2],FIRST_TEN[c-1])
return u.join( req )
elif n>9:
a=n//100
n=n-100*(n//100)
b=n
n=n-10*(n//10)
c=n
print(n)
if b<20 and b>9:
req= (SECOND_TEN[n-(b//10)*10])
return req
else:
if c==0:
req= (OTHER_TENS[(b//10)-2])
return req
else:
req= (OTHER_TENS[b//10-2],FIRST_TEN[c-1])
return u.join( req )
else:
a=n//100
n=n-100*(n//100)
b=n
n=n-10*(n//10)
c=n
print(FIRST_TEN[c-1])
return FIRST_TEN[c-1]
return 0
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(4) == 'four', "1st example"
assert checkio(133) == 'one hundred thirty three', "2nd example"
assert checkio(12) == 'twelve', "3rd example"
assert checkio(101) == 'one hundred one', "4th example"
assert checkio(212) == 'two hundred twelve', "5th example"
assert checkio(40) == 'forty', "6th example"
assert not checkio(212).endswith(' '), "Don't forget strip whitespaces at the end of string"
Oct. 21, 2017