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First solution in Speedy category for Sort Except Zero by amorvan23a
from typing import Iterable
def except_zero(items: list) -> Iterable:
zeros = [i for i,x in enumerate(items) if x==0] # buscando elementos(0) en lista
nums = [x for i,x in enumerate(items) if x!=0] # eliminando zeros de la lista
nums.sort() #ordenando elementos
for i in zeros: nums.insert(i,0) # aƱadiendo zeros en su posiciĆ³n natural
return nums
if __name__ == '__main__':
print("Example:")
print(list(except_zero([5, 3, 0, 0, 4, 1, 4, 0, 7])))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(except_zero([5, 3, 0, 0, 4, 1, 4, 0, 7])) == [1, 3, 0, 0, 4, 4, 5, 0, 7]
assert list(except_zero([0, 2, 3, 1, 0, 4, 5])) == [0, 1, 2, 3, 0, 4, 5]
assert list(except_zero([0, 0, 0, 1, 0])) == [0, 0, 0, 1, 0]
assert list(except_zero([4, 5, 3, 1, 1])) == [1, 1, 3, 4, 5]
assert list(except_zero([0, 0])) == [0, 0]
print("Coding complete? Click 'Check' to earn cool rewards!")
May 26, 2020