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Sort by Extension solution in Uncategorized category for Sort by Extension by vvm70
from typing import List
def sort_by_ext(files: List[str]) -> List[str]:
s1 = sorted(filter(lambda x: x.rfind('.') in (-1, 0, len(x) - 1), files))
s2 = sorted(set(files) - set(s1), key=lambda x: (x[x.rfind('.') + 1:], x))
return s1 + s2
if __name__ == '__main__':
print("Example:")
print(sort_by_ext(['1.cad', '1.bat', '2.aa']))
# These "asserts" are used for self-checking and not for an auto-testing
assert sort_by_ext(['1.cad', '1.bat', '2.aa']) == ['2.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '2.bat']) == ['1.aa', '1.bat', '2.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.bat']) == ['.bat', '1.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '.aa', '.bat']) == ['.aa', '.bat', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.', '1.aa']) == ['1.', '1.aa', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '1.aa.doc']) == ['1.aa', '1.bat', '1.cad', '1.aa.doc']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.aa.doc']) == ['1.aa', '1.bat', '1.cad', '.aa.doc']
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May 10, 2020