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First solution in Clear category for Sort Array by Element Frequency by yuwai
def frequency_sort(items):
d=dict()
for item in items:
if item not in d:
d[item]=1
else:
d[item]+=1
temp=sorted(d.items(),key=lambda x:x[1],reverse=True)
result=[]
for x in temp:
for y in range(d[x[0]]):
result.append(x[0])
return result
if __name__ == '__main__':
print("Example:")
print(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
assert list(frequency_sort(['bob', 'bob', 'carl', 'alex', 'bob'])) == ['bob', 'bob', 'bob', 'carl', 'alex']
assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
assert list(frequency_sort([])) == []
assert list(frequency_sort([1])) == [1]
print("Coding complete? Click 'Check' to earn cool rewards!")
Dec. 20, 2018