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First Sort Array by Element Frequency solution in Clear category for Sort Array by Element Frequency by Wakko_Warner
def frequency_sort(items):
# your code here
d = {x:items.count(x) for x in items}
result =[]
for i in (sorted (d.items(), key = lambda kv : (kv[1]), reverse = True)):
result.extend([i[0]]*i[1])
return result
Dec. 1, 2020