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First solution in Clear category for Similar Triangles by wo.tomasz
import math
from typing import List, Tuple
Coords = List[Tuple[int, int]]
def cal_len(coords: Coords)-> list:
ll = []
for ind in range(len(coords)):
x1, y1 = coords[ind-1]
x2, y2 = coords[ind]
ll.append(math.sqrt(math.pow((x2 - x1), 2) + math.pow((y2 - y1), 2)))
ll.sort()
return ll
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
lens1 = cal_len(coords_1)
lens2 = cal_len(coords_2)
return lens1[0]/lens2[0] == lens1[1]/lens2[1] and lens1[1]/lens2[1] == lens1[2]/lens2[2]
if __name__ == '__main__':
print("Example:")
print(similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]))
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
Dec. 6, 2020