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First solution in Clear category for Similar Triangles by Jaime
from typing import List, Tuple
Coords = List[Tuple[int, int]]
def dist (a,b): return ((a[0]-b[0])**2+(a[1]-b[1])**2)
def ord(x): return sorted([dist(x[0],x[1]),dist(x[0],x[2]),dist(x[1],x[2])])
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
a,b,c=ord(coords_1); a2,b2,c2=ord(coords_2)
return True if a/a2==b/b2==c/c2 else False
if __name__ == '__main__':
print("Example:")
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
May 6, 2020
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