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Similar Triangles solution in Clear category for Similar Triangles by Elena_Korljukova
from typing import List, Tuple
Coords = List[Tuple[int, int]]
def cut_length(a,b):
s=(a[0]-b[0])**2+(a[1]-b[1])**2 #длина стороны в квадрате
return s
def triangle(x):
side1 = cut_length(x[0],x[1]) #квадрат первой стороны
side2 = cut_length(x[1],x[2]) #квадрат второй стороны
side3 = cut_length(x[0],x[2]) #квадрат третьей стороны
a=sorted([side1, side2, side3])
return a
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
w1=triangle(coords_1) #квадраты длин сторон первого треугольника
w2=triangle(coords_2) #квадраты длин сторон второго треугольника
if w1[0]/w2[0]==w1[1]/w2[1] and w1[0]/w2[0]==w1[2]/w2[2]:
return True
else:
return False
if __name__ == '__main__':
print("Example:")
print(similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]))
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
May 1, 2020
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