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First solution in Clear category for Roman Numerals by sts10131
def checkio(data):
d=data
s=''
while d>=1000:
s+='M'
d-=1000
if d>=900:
s+='CM'
d-=900;
if d>=500:
s+='D'
d-=500
if d>=400:
s+='CD'
d-=400
while d>=100:
s+='C'
d-=100
if d>=90:
s+='XC'
d-=90;
if d>=50:
s+='L'
d-=50
if d>=40:
s+='XL'
d-=40
while d>=10:
s+='X'
d-=10
if d>=9:
s+='IX'
d-=9;
if d>=5:
s+='V'
d-=5
if d>=4:
s+='IV'
d-=4
while d>=1:
s+='I'
d-=1
#replace this for solution
return s
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
Dec. 27, 2016