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First solution in Uncategorized category for Roman Numerals by old_user
# migrated from python 2.7
def checkio(number):
'return roman numeral using the specified integer value from range 1...3999'
units = ['I', 'II', 'III', 'IV', 'V', 'VI', 'VII', 'VIII', 'IX']
tens = ['X', 'XX', 'XXX', 'XL', 'L', 'LX', 'LXX', 'LXXX', 'XC']
hundreds = ['C', 'CC', 'CCC', 'CD', 'D', 'DC', 'DCC', 'DCCC', 'CM']
res = ''
res += 'M' * (number // 1000)
res += hundreds[((number//100)%10)-1] if ((number//100)%10) else ''
res += tens[((number//10)%10)-1] if ((number//10)%10) else ''
res += units[(number%10)-1] if (number%10) else ''
return res
if __name__ == '__main__':
assert checkio(6) == 'VI', 'First'
assert checkio(76) == 'LXXVI', 'Second'
print('All ok')
April 15, 2011
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